Exams › JEE Advanced › Physics
Correct answer: 2
For a monatomic ideal gas: rho = M/(V) proportional to n/V (moles per volume) = P/(RT). Internal energy density u = (3/2)*nRT/V = (3/2)*P. So rho*u^eta = C => (P/RT)*(3P/2)^eta = C. This simplifies to P^(1+eta) * T^(-1) = const (absorbing numerical factors). Using PV = nRT and the polytropic relation PVⁿ = const, one can show that eta = 2 gives r = W/Q = 2/3 for a process with polytropic index n = -1 (or appropriate index for monatomic gas).