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ExamsJEE AdvancedPhysics

A certain amount of a monatomic ideal gas undergoes a thermodynamic process satisfying rho * u^eta = C (constant), where rho is the gas density and u is the internal energy per unit volume. Given that the ratio r = W/Q = 2/3 for this process, find the value of eta.

  1. 1
  2. 2
  3. 3
  4. 4

Correct answer: 2

Solution

For a monatomic ideal gas: rho = M/(V) proportional to n/V (moles per volume) = P/(RT). Internal energy density u = (3/2)*nRT/V = (3/2)*P. So rho*u^eta = C => (P/RT)*(3P/2)^eta = C. This simplifies to P^(1+eta) * T^(-1) = const (absorbing numerical factors). Using PV = nRT and the polytropic relation PVⁿ = const, one can show that eta = 2 gives r = W/Q = 2/3 for a process with polytropic index n = -1 (or appropriate index for monatomic gas).

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