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What is the ratio of the wavelength of the second line of the Balmer series to the wavelength of the first line of the Lyman series for a hydrogen-like atom?

1. 1/2
2. 2/3
3. 3/4
4. 4/5

Correct answer: 4/5

Solution

Balmer 2nd line uses transitions from n=4 to n=2, and Lyman 1st line uses n=2 to n=1. The ratio of their wavelengths is 20/25 = 4/5.

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