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A steel plate with face area 4 cm² and thickness 0.5 cm is rigidly fixed at its lower surface. A shear force of 9.6 N is applied parallel to the upper surface. Find the lateral displacement of the upper surface. (Modulus of rigidity of steel = 8 * 10¹⁰ N/m²)
- 1.5 * 10⁻⁹ m
- 1.5 * 10⁻⁸ m
- 1.5 * 10⁻¹⁰ m
- 1.5 * 10⁻⁷ m
Correct answer: 1.5 * 10⁻⁹ m
Solution
deltaₓ = F*L/(G*A) = 9.6 * 0.005 / (8*10¹⁰ * 4*10⁻⁴) = 0.048 / (3.2*10⁷) = 1.5 * 10⁻⁹ m.
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