A rectangular block with dimensions a (along force direction), b (width), and c (height) is fixed to the ground. A horizontal force F is applied on the top face. If eta is the modulus of rigidity, what is the shear strain angle phi?

F/(a*b*eta)
F/(a*c*eta)
F/(b*c*eta)
F/sqrt(b²+c²)*eta

Correct answer: F/(a*b*eta)

Solution

Force F is applied horizontally on the top face of area a*b. Shear stress tau = F/(a*b). Shear strain phi = tau/eta = F/(a*b*eta).

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