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A helicopter flying horizontally at a constant speed of 180 km/hr drops a box directly above a point A on an inclined plane. The box lands 10 seconds later at point B on the inclined surface. Given that h is the vertical drop (in metres) and d is the horizontal distance travelled (in metres), find the value of h / 20.

1. 20
2. 25
3. 30
4. 50

Correct answer: 25

Solution

With t = 10 s and g = 10 m/s², vertical drop h = (1/2)(10)(10²) = 500 m. Hence h / 20 = 500 / 20 = 25.

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