Exams › JEE Advanced › Physics
A ball is dropped onto a fixed inclined plane and bounces elastically (coefficient of restitution = 1). After successive bounces, the ranges measured along the incline between consecutive bounce points are R1, R2, and R3. If R2 = (R1 + R3) / a, find the value of a.
- 5.5
- 6
- 6.5
- 2
Correct answer: 2
Solution
For elastic bouncing on an inclined plane, the ranges form an arithmetic progression (R1: R2: R3 = 1: 2: 3), so R2 = (R1 + R3)/2, giving a = 2.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →