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ExamsJEE AdvancedPhysics

The angular displacement of a particle is given by theta = omega₀*t + (1/2)*alpha*t², where omega₀ = 1 rad/s and alpha = 1.5 rad/s² are constants. Find the angular velocity (in rad/s) at t = 2 s.

  1. 2 rad/s
  2. 3 rad/s
  3. 4 rad/s
  4. 5 rad/s

Correct answer: 4 rad/s

Solution

From theta = omega₀*t + (1/2)*alpha*t², differentiating: omega = d(theta)/dt = omega₀ + alpha*t. At t = 2 s: omega = 1 + 1.5*2 = 1 + 3 = 4 rad/s.

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