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In a series RLC circuit, the readings of voltmeters V1 and V2 are 100 V and 120 V respectively, and the source voltage is 130 V. Voltmeter V1 measures voltage across R, and V2 measures voltage across the series combination of L and C. Identify the correct statement(s).

1. Voltages across resistor, inductor, and capacitor are 50 V, 86.6 V, and 206.6 V respectively
2. Voltages across resistor, inductor, and capacitor are 10 V, 90 V, and 30 V respectively
3. Power factor of the circuit is 5/13
4. Circuit is capacitive in nature

Correct answer: Voltages across resistor, inductor, and capacitor are 50 V, 86.6 V, and 206.6 V respectively

Solution

With V1 measuring V_RL=100V (phasor sum of R and L), V2=Vc=120V, and source=130V, we find V_R=50V, V_L=86.6V, V_C=206.6V, confirming option A. The power factor is V_R/V_source=50/130=5/13 (option C correct). Since V_C > V_L, the circuit is capacitive (option D correct). Option A correctly identifies the individual voltages.

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