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ExamsJEE AdvancedPhysics

A composite rod consists of a steel segment (length 25 cm, cross-sectional area 2A) and a copper segment (length 50 cm, cross-sectional area A) joined end to end. An axial load F is applied. The Young's modulus of steel to copper is 2:1. Which of the following statements are INCORRECT?

  1. The extension produced in the copper rod will be more.
  2. The extensions in the copper and steel parts are in the ratio 2:1.
  3. The stress applied to the copper rod will be more.
  4. No extension will be produced in the steel rod.

Correct answer: The extensions in the copper and steel parts are in the ratio 2:1.

Solution

Both segments carry force F. Yₛ = 2*Y_c. deltaₛ = F*Lₛ/(Aₛ*Yₛ) = F*0.25/(2A*2Y_c) = 0.25F/(4AY_c) = F/(16AY_c). delta_c = F*L_c/(A_c*Y_c) = F*0.5/(A*Y_c) = 0.5F/(AY_c). delta_c/deltaₛ = (0.5)/(1/16) = 8. So copper extension is 8x steel (Statement A: copper is more - CORRECT). Ratio is 8:1 not 2:1 (Statement B: INCORRECT). Stress on copper = F/A, stress on steel = F/(2A); copper stress is higher (Statement C: CORRECT). Steel does extend (Statement D: INCORRECT). B and D are incorrect.

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