Exams › JEE Advanced › Physics
In a circuit, a 20 V battery is connected such that resistors of 6 ohm, 4 ohm, 8 ohm, and 12 ohm form a Wheatstone-bridge arrangement. An ammeter is connected in the middle (galvanometer) branch. What does the ammeter read?
- 0 A
- 1/2 A
- 1 A
- 2 A
Correct answer: 0 A
Solution
With arms 6 ohm and 12 ohm in one pair and 4 ohm and 8 ohm in the other pair, the ratios 6/12 = 4/8 = 1/2 satisfy the balance condition, so no current flows through the middle branch and the ammeter reads 0 A.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →