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ExamsJEE AdvancedPhysics

A particle moves in a circle of radius r = 2 m with speed varying as v = 2t m/s. Match each value in Column-I with the correct physical quantity in Column-II. Column-I (values): (A) 2 (B) 18 (C) 45 (D) 90 Column-II (physical quantities): (P) Centripetal acceleration (m/s²) at t = 3 s (Q) Tangential acceleration (m/s²) at t = 1 s (R) Tangential acceleration (m/s²) at t = 2 s (S) Angle rotated (in degrees) in time sqrt(pi) s (T) Angle (in degrees) between net acceleration and velocity at t = 1 s Which Column-II entry matches with (A) = 2?

  1. (P)
  2. (Q)
  3. (R)
  4. (S)

Correct answer: (Q)

Solution

Tangential acceleration = dv/dt = 2 m/s² (constant), so value 2 matches (Q) tangential acceleration at t=1 s (and also R at t=2 s, but Q is the primary listed match). Full mapping: A->Q (and R), B->P, C->T, D->S.

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