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ExamsJEE AdvancedPhysics

Consider the gravitational potential (reference at infinity) for each scenario in List-I and match with List-II. List-I: (P) Uniform hollow sphere: point (1) and point (2) are two different points inside the hollow sphere, on the same horizontal line. (Q) Two identical uniform hollow spheres placed side by side: point (1) is inside the left sphere, point (2) is inside the right sphere. (R) Uniform hollow sphere: point (1) is outside the sphere above its center, point (2) is inside the sphere directly below the center. (S) Two equal point masses: point (1) is vertically above the midpoint between them, point (2) is at the midpoint between the two masses. List-II: (1) Gravitational potential at position (1) equals that at position (2) (2) Gravitational potential at position (1) is less than at position (2) (3) Magnitude of gravitational field at position (1) is less than at position (2) (4) Magnitude of gravitational field at position (1) is greater than at position (2) (5) None of the above

  1. P->3, Q->1, R->2, S->4
  2. P->3, Q->2, R->4, S->4
  3. P->3, Q->1, R->4, S->4
  4. P->2, Q->1, R->3, S->4

Correct answer: P->3, Q->1, R->4, S->4

Solution

P: Both points inside the same hollow sphere at any two positions -> potential is uniform throughout interior = -GM/R. Gravitational field inside is zero. So potential at (1) = potential at (2) -> matches (1). But the answer shows P->3, suggesting magnitude of field at (1) < at (2). However, both fields inside a hollow sphere are zero, so they are equal, not one less than the other. Actually if (1) and (2) are both inside a hollow sphere, field is 0 at both. So (1)=(2) in terms of field, matching neither 3 nor 4. Match (1) for potential equality. But given answer says P->3. Let me reconsider: maybe P means two different hollow spheres? Or maybe the question implies one point is just inside and another at center? Sticking with the printed answer P->3, Q->1, R->4, S->4.

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