A ball of mass 2 kg is dropped from the top of a building 20 m tall. A constant horizontal wind applies a force of 8 N on the ball throughout its fall. What is the horizontal range of the ball when it hits the ground?

4 m
8 m
16 m
2 m

Correct answer: 8 m

Solution

Vertical: h = (1/2)*g*t² => 20 = (1/2)*10*t² => t = 2 s. Horizontal: aₕ = F/m = 8/2 = 4 m/s². Range = (1/2)*4*(2)² = 8 m.

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