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A point charge of 10⁻⁸ C is located at coordinates (4 m, 7 m, 2 m). Calculate the electric potential (in volts) at the point (1 m, 3 m, 2 m). (Take k = 9 * 10⁹ N m² C⁻²)
- 9 V
- 18 V
- 27 V
- 36 V
Correct answer: 18 V
Solution
The separation between the charge and the field point is r = sqrt((4-1)² + (7-3)² + (2-2)²) = sqrt(9 + 16 + 0) = 5 m. Electric potential V = kQ/r = (9 * 10⁹ * 10⁻⁸) / 5 = 90/5 = 18 V.
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