Two fusion reactions proceed as follows: Reaction 1: H-2 + H-2 -> H-3 + H-1 + 4.0 MeV Reaction 2: H-3 + H-2 -> He-4 + n + 17.6 MeV The net result: 3 H-2 -> He-4 + H-1 + n + 21.6 MeV What is the energy released per nucleon of the reactants?

1.8 MeV
3.6 MeV
7.2 MeV
21.6 MeV

Correct answer: 3.6 MeV

Solution

The net reaction consumes 3 deuterium nuclei (H-2), each with 2 nucleons. Total nucleons in reactants = 3 * 2 = 6. Total energy released = 21.6 MeV. Energy per nucleon = 21.6 / 6 = 3.6 MeV.

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