Exams › JEE Advanced › Physics

Four tuning forks having frequencies 200 Hz, 201 Hz, 204 Hz and 206 Hz are all vibrated simultaneously. The resulting beat frequency is:

1. 6
2. 12
3. 15
4. None of these

Correct answer: None of these

Solution

With forks at 200, 201, 204, 206 Hz, the six pairwise beat frequencies are 1, 2, 3, 4, 5, and 6 Hz simultaneously. No single value of 6, 12, or 15 Hz correctly describes the situation.

Related JEE Advanced Physics questions

• A wave pulse traveling to the right along the x-axis is described by the equation y(x, t) = 2.0 / ((x − 3.0t)² + 1), where x and y are measured in centimeters and t is in seconds. The peak height of the pulse is defined as the largest displacement along the y-axis. Which of the following is true?
• When a person blows into one end of a long pipe, creating a high-pressure air pulse that moves through it, what happens when this pulse reaches the opposite end of the pipe?
• Under which condition can stationary waves form?
• Four harmonic waves of equal frequencies and equal intensities I₀ have phase angles 0, π/3, 2π/3, and π. When they are superposed, the intensity of the resulting wave is nI₀. The value of n is
• A string that is 1 meter long and has a mass of 2 × 10⁻⁵ kg is stretched under a tension T. When vibrating, it produces two consecutive harmonics with frequencies of 750 Hz and 1000 Hz. What is the value of the tension T in Newtons?
• A plane progressive wave travels in the +x direction and is described by y = 0.02 sin(8*pi*(t - x/20)). It is reflected at a rarer medium (a medium in which wave speed is higher) at x = 0. The amplitude of the reflected wave is 75% of the incident amplitude. What is the equation of the reflected wave?

⚔️ Practice JEE Advanced Physics free + battle 1v1 →