A block of mass 10 kg begins sliding on a horizontal surface with an initial velocity of 9.8 m/s. The coefficient of kinetic friction between the block and the surface is 0.5. How far does the block travel before stopping? (Take g = 9.8 m/s²)

4.9 m
9.8 m
12.5 m
19.6 m

Correct answer: 9.8 m

Solution

Deceleration due to friction: a = mu * g = 0.5 * 9.8 = 4.9 m/s². Final velocity = 0. Using v² = u² - 2*a*s: 0 = (9.8)² - 2 * 4.9 * s. s = (9.8)² / (2 * 4.9) = 96.04 / 9.8 = 9.8 m.

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