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ExamsJEE AdvancedPhysics

An ideal gas undergoes isothermal expansion from volume V1 to V2 (V2 > V1) starting at pressure P1. It is then compressed adiabatically back to its original volume V1, reaching final pressure P3. If W is the total work done by the gas in both processes, which statement is correct?

  1. P3 > P1, W > 0
  2. P3 < P1, W < 0
  3. P3 > P1, W < 0
  4. P3 = P1, W = 0

Correct answer: P3 > P1, W < 0

Solution

During isothermal expansion (V1->V2 at T_initial), work done by gas W_iso = nRT*ln(V2/V1) > 0. After isothermal step, gas is at T_initial and pressure P1*V1/V2 < P1. During adiabatic compression back to V1: temperature rises above T_initial (since no heat is released), so final pressure P3 = nRT_f/V1 > nRT_initial/V1 = P1. Work done BY gas in adiabatic compression = -nCv*(T_f - T_initial) < 0 (work is done ON the gas). The adiabat is steeper than the isotherm on a PV diagram, so |W_adi| > |W_iso|. Total W = W_iso + W_adi < 0.

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