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ExamsJEE AdvancedPhysics

A ball of mass m, moving with speed v, undergoes a perfectly elastic head-on collision with a massive wall that is moving toward the ball with speed u. The collision lasts for time dt. What is the average elastic force exerted on the ball during the collision?

  1. m*(u + v) / dt
  2. 2*m*(u + v) / dt
  3. The kinetic energy of the ball increases by 2*m*(u + v)
  4. The kinetic energy of the ball remains the same after the collision

Correct answer: 2*m*(u + v) / dt

Solution

Taking the wall's direction as positive, ball initial velocity = -v, wall velocity = +u. After elastic collision ball velocity = 2u + v (relative reversal). Change in momentum = m*(2u+v) - m*(-v) = 2m*(u+v). Average force = 2m*(u+v)/dt.

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