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ExamsJEE AdvancedPhysics

A closed organ pipe of length 28 cm (closed at one end) resonates with a tuning fork of frequency 850 Hz. The speed of sound in air is 340 m/s. Which of the following statements are correct? (A) The end correction of the pipe is 1 cm (B) The end correction of the pipe is 2 cm (C) The air column vibrates in its fundamental mode (D) The air column vibrates in the first overtone

  1. The end correction of the pipe is 1 cm
  2. The end correction of the pipe is 2 cm
  3. The air column vibrates in its fundamental mode
  4. The air column vibrates in the first overtone

Correct answer: The end correction of the pipe is 1 cm

Solution

For a closed pipe resonating at frequency f, the effective length is L_eff = (2n-1)*v/(4f). With v=340 m/s, f=850 Hz: L_eff = (2n-1)*340/(4*850) = (2n-1)*0.1 m. For n=1: L_eff=0.10 m; n=2: L_eff=0.30 m; n=3: L_eff=0.50 m. Since L=0.28 m, n=2 gives L_eff=0.30 m, so end correction e = 0.30-0.28 = 0.02 m = 2 cm. n=2 means first overtone (3rd harmonic).

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