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ExamsJEE AdvancedPhysics

A circuit contains a 20 microF capacitor in series with an 8 ohm resistor (top branch), a 4 ohm resistor in a parallel branch, and a 40 V battery with a 4 ohm internal/series resistor. Consider the following statements about this RC circuit: (P) Time constant is 0.1 ms (Q) Charge on the capacitor as a function of time is 400(1 - e^(-10000t)) microC (R) Current through the 8 ohm resistor at t = 0.4 * 10⁻³ s is 0.27 A (S) Charge on the capacitor in steady state is 400 microC Which of the above statements are correct?

  1. Time constant is 0.1 ms
  2. Charge on the capacitor as a function of time is 400 (1-e⁻¹⁰⁰⁰⁰t) microC
  3. Current through 8 ohm resistor at t = 0.4 * 10⁻³ sec is 0.27A
  4. Charge on the capacitor in steady state is 400 microC

Correct answer: Charge on the capacitor in steady state is 400 microC

Solution

In steady state, capacitor is fully charged and no current flows through the 8-ohm + capacitor branch. The current in the circuit is 40/(4+4) = 5 A through the two 4-ohm resistors. Voltage across capacitor = voltage across parallel 4-ohm = 5*4 = 20 V (wait, circuit topology needs clarification). With the described topology, V_cap(steady) = 20 V, so Q = CV = 20*20*10⁻⁶ = 400 microC. Statement S is correct.

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