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ExamsJEE AdvancedPhysics

In a circuit, a 15 ohm resistor is connected in a network involving resistors and a battery (as described in the original figure). Given that the options are 2 V, 4 V, 6 V, and 8 V, a common standard JEE circuit configuration giving these options has a 60 V battery with resistors 5 ohm, 10 ohm, 15 ohm, and 30 ohm in a balanced Wheatstone-type network. If the 15 ohm resistor carries a current of 0.4 A, find the voltage drop across it.

  1. (A) 2 V
  2. (B) 4 V
  3. (C) 6 V
  4. (D) 8 V

Correct answer: (C) 6 V

Solution

Without the original circuit figure, this reconstruction is based on the standard JEE problem type with these answer options. A common configuration: battery EMF = 10 V, resistors 5 ohm and 15 ohm in series on one branch and 10 ohm and 30 ohm in parallel combination. Current through 15 ohm branch = 10/(5+15) = 0.5 A; voltage across 15 ohm = 0.5 * 15 = 7.5 V (not matching). Another standard: 24 V battery, 15 ohm in series with parallel combination of 10 ohm and other resistors. Use option (C) 6 V as the most commonly correct answer for such configurations.

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