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Two stars of masses m and 3m are separated by a distance r and revolve in circular orbits about their common centre of mass under mutual gravitational attraction. The angular velocity of each star is
- sqrt(Gm / (4r³))
- sqrt(2Gm / r³)
- sqrt(4Gm / r³)
- sqrt(Gm / (2r³))
Correct answer: sqrt(4Gm / r³)
Solution
For the star of mass m orbiting at radius 3r/4, equating gravitational pull to centripetal force gives omega² = 4Gm/r³, so omega = sqrt(4Gm/r³). Both stars share the same angular velocity.
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