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ExamsJEE AdvancedPhysics

A body suspended from a spring balance in a stationary ship weighs W. The ship then moves along the equator from west to east with speed v (omega is Earth's angular velocity, m = W/g). What is the approximate reading of the spring balance?

  1. W
  2. W*(1 + v²/R)
  3. W*(1 + 2*v*omega/g)
  4. W*(1 - 2*v*omega*m/W)

Correct answer: W*(1 - 2*v*omega*m/W)

Solution

The extra eastward speed v adds to Earth's rotation, increasing the centrifugal acceleration by 2*omega*v, which reduces the apparent weight by 2*m*omega*v, giving W_apparent = W - 2*m*omega*v = W*(1 - 2*v*omega*m/W).

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