Exams › JEE Advanced › Physics › Probability
2 questions with worked solutions.
Answer: 7
There are four equiprobable-structured paths. In Path A (Red then Red from Urn-II) Urn-I ends with 2R 2W — white count preserved. In Path D (White then White from Urn-II) Urn-I ends with 4R 4W — red count preserved. These are the only two paths satisfying the given condition, so the conditional probability p of red being unchanged equals P(Path D) / (P(Path A) + P(Path D)).
Answer: P(ship is operational | E1 is functioning) = 7/16
P(X) = (1/2)(1/4)(1/4) + (1/2)(1/4)(3/4) + (1/2)(3/4)(1/4) + (1/2)(1/4)(1/4) = 1/32 + 3/32 + 3/32 + 1/32 = 8/32 = 1/4. Then evaluate each option using conditional probability.