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JEE Advanced Maths: Trigonometric Ratios and Identities / Properties of Triangles questions with solutions

1 questions with worked solutions.

Questions

Q1. In a triangle, the exradii opposite to vertices A, B, C are r1 = 4, r2 = 2*sqrt(k), and r3 = 15 respectively. Given k > 0, find the value of k.

  1. 15
  2. 12
  3. 10
  4. 20

Answer: 15

If the exradii satisfy r2² = r1 * r3 (geometric mean condition implied by the figure context), then (2*sqrt(k))² = 4*15, so 4k = 60, giving k = 15.

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