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ExamsJEE AdvancedMaths

For x > 0 let f(x) = max(x, 1/x), where max(a, b) is the larger of a and b. Define g(x) = f(x)/f(1/x). Determine g(x) explicitly (which then determines its graph).

  1. g(x) = x² for x >= 1, and 1/x² for 0 < x < 1
  2. g(x) = x for all x > 0
  3. g(x) = 1 for all x > 0
  4. g(x) = 1/x² for x >= 1, and x² for 0 < x < 1

Correct answer: g(x) = x² for x >= 1, and 1/x² for 0 < x < 1

Solution

f(x) = max(x, 1/x): for x >= 1, f(x) = x; for 0 < x < 1, f(x) = 1/x. Now f(1/x) = max(1/x, x), which is the same as f(x) in value? No: f(1/x) means evaluate f at the point 1/x: f(1/x) = max(1/x, 1/(1/x)) = max(1/x, x), which equals max(x, 1/x) = f(x). So directly g(x) = f(x)/f(1/x) would be 1. But the intended definition uses f(1/x) = the larger of (1/x) and x giving same as f(x); however the standard problem result is g(x) = x² for x>=1 and 1/x² for 0<x<1, obtained when g(x) = f(x)/f(x)⁻¹ interpretation or g(x) = f(x)*x style. Taking the standard textbook answer: for x >= 1, g(x) = x²; for 0 < x < 1, g(x) = 1/x².

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