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Let f(x) = cos x for 0 <= x < pi/2 and f(x) = (pi/2 - x)² for pi/2 <= x < pi, extended periodically with period pi. Which of the following statements is INCORRECT?
- The range of f is [0, pi²/4)
- f is continuous for all real x, but not differentiable for some real x
- f is continuous for all real x
- The area bounded by y = f(x) and the x-axis from x = -n*pi to x = n*pi is 2*n*(1 + pi³/24) for a given n in N
Correct answer: f is continuous for all real x
Solution
At the period boundary the left limit is pi²/4 while the right value is cos 0 = 1; pi²/4 is about 2.47 not equal to 1, so f is NOT continuous everywhere. Thus 'f is continuous for all real x' is the incorrect statement.
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In the intervals (-1, 0) and (0, 2), the second derivative of (f - 3g), denoted as (f - 3g)'', does not become zero at any point. Which of the following statements is true?
- Suppose f: R → (0, 1) is a continuous function. Which of the following functions equals zero at least at one point within the interval (0, 1)?
- Consider the function f(x) = x + ln(x) − x ln(x), where x lies in the interval (0, ∞).
- Column 1 contains details about the zeros of f(x), f'(x), and f''(x).
- Column 2 contains information about the behavior of f(x), f'(x), and f''(x) as x approaches infinity.
- Column 3 contains details about the increasing or decreasing nature of f(x) and f'(x).
Column 1:
(I) f(x) = 0 for some x in (1, e²)
(II) f'(x) = 0 for some x in (1, e)
(III) f'(x) = 0 for some x in (0, 1)
(IV) f''(x) = 0 for some x in (1, e)
Column 2:
(i) lim x→∞ f(x) = 0
(ii) lim x→∞ f(x) = −∞
(iii) lim x→∞ f'(x) = −∞
(iv) lim x→∞ f''(x) = 0
Column 3:
(P) f is increasing on (0, 1)
(Q) f is decreasing on (e, e²)
(R) f' is increasing on (0, 1)
(S) f' is decreasing on (e, e²)
Which of the following options gives the correct combination?
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