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Find the area (in square units) of the region {(x, y) in R²: x² <= y <= 3 - 2x}.

1. 29/3
2. 31/3
3. 34/3
4. 32/3

Correct answer: 32/3

Solution

The curves meet at x = -3 and x = 1; integrating the difference (3 - 2x - x²) over [-3, 1] gives 32/3.

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