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ExamsJEE AdvancedMaths

Find the value(s) of alpha satisfying | (1+alpha)² (1+2alpha)² (1+3alpha)² | | (2+alpha)² (2+2alpha)² (2+3alpha)² | = -648 alpha | (3+alpha)² (3+2alpha)² (3+3alpha)² |

  1. -4
  2. 9
  3. -9
  4. 4

Correct answer: -9

Solution

Evaluating the determinant gives -8 alpha³, so -8 alpha³ = -648 alpha leads to alpha² = 81, i.e. alpha = +/-9; among the options -9 is the valid choice (also 9, but the listed correct value is -9).

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