StreakPeaked· Practice

ExamsJEE AdvancedMaths

Find the constants m and c for which y = mx + c is a solution of the differential equation y'' - 3y' - 4y = -4x.

  1. m = -1, c = 3/4
  2. m = 1, c = -3/4
  3. no such real m, c exist
  4. m = 1, c = 3/4

Correct answer: m = 1, c = -3/4

Solution

Substitution gives -3m - 4(mx + c) = -4x; comparing coefficients gives m = 1 and c = -3/4.

Related JEE Advanced Maths questions

⚔️ Practice JEE Advanced Maths free + battle 1v1 →