Exams › JEE Advanced › Maths
For a Class XI section the following data are recorded: heights have Mean = 162.6 cm and Variance = 127.69 cm²; weights have Mean = 52.36 kg and Variance = 23.1361 kg². Do the weights show greater variation than the heights?
- Yes, because the variance of weights is greater than that of heights.
- No, because the coefficient of variation of heights is greater than that of weights.
- Yes, because the coefficient of variation of weights is greater than that of heights.
- No, because the mean of heights is greater than that of weights.
Correct answer: Yes, because the coefficient of variation of weights is greater than that of heights.
Solution
CV(heights) = (11.3/162.6)*100 ~ 6.95% and CV(weights) = (4.81/52.36)*100 ~ 9.19%; weights have higher CV, so greater variation.
Related JEE Advanced Maths questions
- The standard deviation of a set containing 25 values is 40. If 5 is added to each value in the set, what will the updated standard deviation be?
- Given Σ(xi − 5) = 9 and Σ(xi − 5)² = 45 for a dataset of 9 values x1, x2,..., x9, what is the standard deviation of the data?
- The variables X and U are connected by the equation X = 5 + 2U. If the mean of X is 10 and its coefficient of variation is 2.6, what is the coefficient of variation for U?
- What is the average absolute deviation from the mean for the arithmetic progression a, a + d, a + 2d,..., a + 2nd?
- What is the variance of the first n positive integers?
- Seven real numbers 9 = x1 < x2 <... < x7 form an arithmetic progression with common difference d. If their standard deviation is 4 and their mean is x_bar, find the value of x_bar + x6.
⚔️ Practice JEE Advanced Maths free + battle 1v1 →