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Given dy/dx = e^(-2y) with y = 0 at x = 5, find the value of x when y = 3.
- e⁵
- e⁶ + 1
- (e⁶ + 9)/2
- logₑ 6
Correct answer: (e⁶ + 9)/2
Solution
Integrating gives e^(2y)/2 = x + C; using (5, 0) gives C = -9/2, so at y = 3, x = (e⁶ + 9)/2.
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