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Find the area (in square units) enclosed by the parabola y = x² - 1, the tangent to it at the point (2, 3), and the y-axis.

1. 14/3
2. 56/3
3. 8/3
4. 32/3

Correct answer: 8/3

Solution

Between x=0 and x=2 the parabola lies above the tangent; area = integral₀² [(x² - 1) - (4x - 5)] dx = 8/3.

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