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Find the area of the region enclosed between the parabolas y² = 4x and x² = 4y.

1. 0
2. 32/3
3. 16/3
4. 8/3

Correct answer: 16/3

Solution

Between x = 0 and 4, the upper curve is y = 2sqrt(x) and lower is y = x²/4; the area is 16/3.

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