Exams › JEE Advanced › Maths
If the determinant of [[a1 + b1 x, a1 x + b1, c1], [a2 + b2 x, a2 x + b2, c2], [a3 + b3 x, a3 x + b3, c3]] equals 0, which of the following is/are possible conditions?
- x = 1 for all a_i, b_i
- x = -1 for all a_i, b_i
- the determinant of [[a1, b1, c1], [a2, b2, c2], [a3, b3, c3]] = 0
- x = +/-2 for all a_i, b_i
Correct answer: the determinant of [[a1, b1, c1], [a2, b2, c2], [a3, b3, c3]] = 0
Solution
The determinant factors to (1 - x²)*det[[a_i],[b_i],[c_i]], so it vanishes when x = +/-1 or when det[[a1,b1,c1],...] = 0; the condition guaranteed for all a_i, b_i is that this latter determinant is zero (the x = +/-1 options only work in conjunction). The always-sufficient condition is det[[a_i, b_i, c_i]] = 0.
Related JEE Advanced Maths questions
- What is the nature of the solution for the equations x + y + z = 3, 2x + y + 2z = 5, and x − y + 3z = 3?
- What is the nature of the solutions for the equations x + y + z = 3, 2x + 2y + 2z = 7, and x − y + 3z = 3?
- Consider the matrix M = [0 1 a; 1 2 3; 3 b 1] and its adjugate adj M = [-1 1 -1; 8 -6 2; -5 3 -1], where a and b are real numbers. Which of the following statements is/are true?
- Given that the 3x3 determinant |x, 2, x; x², x, 6; x, 1, x| equals Ax⁴ + Bx³ + Cx² + Dx + E, find the sum of the digits of the square of (5A + 4B + 3C + 2D + E).
- The determinant with rows (x², (y+z)², yz), (y², (x+z)², zx), (z², (x+y)², xy) is divisible by which of the following?
- Consider the determinant equation: det([[a1 + b1*x, a1*x + b1, c1], [a2 + b2*x, a2*x + b2, c2], [a3 + b3*x, a3*x + b3, c3]]) = 0. Which of the following are possible conditions that guarantee this holds for all choices of ai, bi, ci?
⚔️ Practice JEE Advanced Maths free + battle 1v1 →