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If y = (2x/pi - 1) cosec x is a solution of the differential equation dy/dx + P(x) y = (2/pi) cosec x on 0 < x < pi/2, find P(pi/4).
- 1
- 0
- 1/2
- sqrt(2)
Correct answer: 1
Solution
Substituting y and y' into the equation reduces P(x) to cot x, so P(pi/4) = cot(pi/4) = 1.
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