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Given sin A = 11/61 (A acute), find tan A, cos A and sec A.

1. tan A = 11/60, cos A = 60/61, sec A = 61/60
2. tan A = 60/11, cos A = 11/61, sec A = 61/11
3. tan A = 11/60, cos A = 61/60, sec A = 60/61
4. tan A = 60/61, cos A = 11/60, sec A = 60/11

Correct answer: tan A = 11/60, cos A = 60/61, sec A = 61/60

Solution

With opposite = 11 and hypotenuse = 61, the adjacent side is 60, giving cos A = 60/61, tan A = 11/60, sec A = 61/60.

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