Exams › JEE Advanced › Maths
In a triangle ABC, sin A - cos B = cos C, with angle B greater than angle C. Find angle B.
- pi/2
- pi/3
- pi/4
- pi/6
Correct answer: pi/2
Solution
Substituting sin A = sin(B+C) and using sum-to-product leads to a factor giving cos(B/2...); solving with B > C yields B = pi/2.
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