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The foci of the ellipse x²/16 + y²/b² = 1 coincide with the foci of the hyperbola x²/144 - y²/81 = 1/25. Find b².
- 7
- 5
- 9
- 4
Correct answer: 7
Solution
Hyperbola c² = (144 + 81)/25 = 9; setting ellipse 16 - b² = 9 gives b² = 7.
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