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One end of a focal chord of the parabola y² = 32x is the point (2, -8). Find the coordinates of the other end of this focal chord.

1. (32, 32)
2. (32, -32)
3. (-2, 8)
4. (2, 8)

Correct answer: (32, 32)

Solution

With a = 8, the point (2, -8) has parameter t = -1/2, so the other end has parameter 2, giving (32, 32).

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