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Let p and q be non-zero reals. The equation (p x² + q y² + r)(4x² + 4y² - 8x - 4) = 0 represents which of the following?
- two straight lines and a circle, when r = 0 and p, q have opposite signs.
- two circles, when p = q and r has sign opposite to p.
- a hyperbola and a circle, when p and q have opposite signs and r is not 0.
- a circle and an ellipse, when p and q are unequal but of the same sign and r has sign opposite to p.
Correct answer: a hyperbola and a circle, when p and q have opposite signs and r is not 0.
Solution
The factor 4(x² + y² - 2x - 1) = 0 is a circle. The factor p x² + q y² + r = 0 is a hyperbola when p and q have opposite signs and r != 0. So that pairing is correct.
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