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Show that sin((n+1)A) sin((n+2)A) + cos((n+1)A) cos((n+2)A) simplifies to cos(A). Which value does the expression equal?
- cos(A)
- sin(A)
- cos(2A)
- -cos(A)
Correct answer: cos(A)
Solution
By the cosine difference identity, the expression equals cos((n+2)A - (n+1)A) = cos(A).
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