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A normal chord is drawn to the parabola y² = 4ax at the point where the ordinate equals the abscissa. Find the angle this normal chord subtends at the focus.
- pi/4
- tan⁻¹(sqrt(2))
- tan⁻¹(2)
- pi/2
Correct answer: pi/2
Solution
The point with ordinate = abscissa is (4a, 4a) (t = 2); the normal meets the curve again, and the focal angle works out to a right angle.
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