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P is any point on an ellipse with foci S1 and S2 and eccentricity 1/2. Let angle PS1S2 = alpha, angle PS2S1 = beta, and angle S1PS2 = gamma. Then cot(alpha/2), cot(gamma/2), cot(beta/2) are in which progression?
- A.P.
- G.P.
- H.P.
- NOT A.P., G.P. or H.P.
Correct answer: A.P.
Solution
Applying the half-angle cotangent formulas in the focal triangle and using r1+r2 = 2a, S1S2 = 2ae shows the three cotangents form an arithmetic progression.
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