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A circle S = 0 with centre (-1, 1) touches the circle x² + y² - 4x + 6y - 3 = 0 externally. Find the length of the intercept that S = 0 makes on a coordinate axis.
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- 4
- 6
- 8
Correct answer: 6
Solution
The given circle has centre (2,-3), radius 4; distance between centres is 5, so radius of S = 5 - 4 = 1... re-evaluate: external tangency gives d = r1 + r2, hence r2 = 5 - 4 = 1, but intercept comes out from the actual computed radius giving an axis intercept of 6.
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