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For the data set 5, 5, 7, 10, 12, 12, 14, 15, match each item in List-I with the correct value in List-II. List-I: (A) Sum of digits of [variance] (where [.] is the greatest integer function); (B) Twice the sum of mean deviation about median and mean deviation about mean; (C) Value of [standard deviation]; (D) Absolute difference of median and mean. List-II: (I) 13; (II) 3; (III) 4; (IV) 1.

1. (A) - I, (B) - III, (C) - II, (D) - IV
2. (A) - III, (B) - II, (C) - IV, (D) - I
3. (A) - IV, (B) - II, (C) - IV, (D) - I
4. (A) - III, (B) - I, (C) - II, (D) - IV

Correct answer: (A) - III, (B) - I, (C) - II, (D) - IV

Solution

Mean = 80/8 = 10; Median = (10+12)/2 = 11; Variance = 108/8 = 13.5; [Variance] = 13; digit sum = 4 -> (III). SD = sqrt(13.5) = 3.67; [SD] = 3 -> (II). Both MD (about mean) and MD (about median) = 26/8 = 3.25; 2*(3.25+3.25) = 13 -> (I). |11-10| = 1 -> (IV). So A-III, B-I, C-II, D-IV.

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