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Correct answer: local maximum at x = 1
f'(x) = [(x-1)(x-2)²(5-x)] / e^x. At x=1, f' changes sign from negative to positive giving a local minimum (not maximum); but since the factor (x-1)² makes x=1 a double root with no sign change in f', x=1 is actually a point of inflection. At x=2, f' does not change sign (even power factor), so x=2 is also a point of inflection.