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ExamsJEE AdvancedMaths

The value of N = sumₖ₌₀¹⁰ C(30+k, k) * C(20-k, 10-k) = C(30,0)*C(20,10) + C(31,1)*C(19,9) + C(32,2)*C(18,8) +... + C(40,10)*C(10,0). Which of the following are INCORRECT?

  1. N is divisible by 10
  2. N is divisible by 3
  3. If N = C(x,y) for some x,y in positive integers, then (x+y) can equal 61
  4. N is divisible by 13

Correct answer: N is divisible by 13

Solution

By the Chu-Vandermonde identity, N = C(51,10) = 12777711870. This is divisible by 10 (ends in 0), divisible by 3 (digit sum 48), and equals C(51,10) so x+y=61 is achievable. It is NOT divisible by 13 (12777711870/13 is not an integer). So option D ('N is divisible by 13') is the INCORRECT statement.

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