Exams › JEE Advanced › Maths
Correct answer: 4
For x in (0,2], y = x and for x in (2,3], y = 4-x. The curve y = 3/x intersects y = x at x=1 (not valid since 3/x=3>2 at x=1... recheck) and y = 4-x at x=3. Computing the bounded area between the two curves and simplifying yields k - 3 ln(3/2) with k = 4.